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29 out of 50 seats in the Iowa Senate 26 seats needed for a majority | ||||||||||||||||
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| Elections in Iowa |
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The 1912 Iowa Senate elections took place as part of the biennial 1912 United States elections. Iowa voters elected state senators in 29 of the senate's 50 districts. State senators serve four-year terms in the Iowa Senate.
A statewide map of the 50 state Senate districts in the 1912 elections is provided by the Iowa General Assembly here.
The primary election on June 3, 1912, determined which candidates appeared on the November 5, 1912 general election ballot.[1][2]
Following the previous election, Republicans had control of the Iowa Senate with 34 seats to Democrats' 16 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 10 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1912 general election with the balance of power shifting to Republicans holding 32 seats and Democrats having 18 seats (a net gain of 2 seats for Democrats).
Summary of Results
- Note: 21 districts with holdover Senators not up for re-election are not listed on this table.