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In vector calculus, the divergence theorem, also known as Gauss's theorem or Ostrogradsky's theorem,^[1] is a theorem relating the flux of a vector field through a closed surface to the divergence of the field in the volume enclosed.

More precisely, the divergence theorem states that the surface integral of a vector field over a closed surface, which is called the "flux" through the surface, is equal to the volume integral of the divergence over the region enclosed by the surface. Intuitively, it states that "the sum of all sources of the field in a region (with sinks regarded as negative sources) gives the net flux out of the region".

The divergence theorem is an important result for the mathematics of physics and engineering, particularly in electrostatics and fluid dynamics. In these fields, it is usually applied in three dimensions. However, it generalizes to any number of dimensions. In one dimension, it is equivalent to the fundamental theorem of calculus. In two dimensions, it is equivalent to Green's theorem.

Explanation using liquid flow

Vector fields are often illustrated using the example of the velocity field of a fluid, such as a gas or liquid. A moving liquid has a velocity—a speed and a direction—at each point, which can be represented by a vector, so that the velocity of the liquid at any moment forms a vector field. Consider an imaginary closed surface S inside a body of liquid, enclosing a volume of liquid. The flux of liquid out of the volume at any time is equal to the volume rate of fluid crossing this surface, i.e., the surface integral of the velocity over the surface.

Since liquids are incompressible, the amount of liquid inside a closed volume is constant; if there are no sources or sinks inside the volume then the flux of liquid out of S is zero. If the liquid is moving, it may flow into the volume at some points on the surface S and out of the volume at other points, but the amounts flowing in and out at any moment are equal, so the net flux of liquid out of the volume is zero.

However if a source of liquid is inside the closed surface, such as a pipe through which liquid is introduced, the additional liquid will exert pressure on the surrounding liquid, causing an outward flow in all directions. This will cause a net outward flow through the surface S. The flux outward through S equals the volume rate of flow of fluid into S from the pipe. Similarly if there is a sink or drain inside S, such as a pipe which drains the liquid off, the external pressure of the liquid will cause a velocity throughout the liquid directed inward toward the location of the drain. The volume rate of flow of liquid inward through the surface S equals the rate of liquid removed by the sink.

If there are multiple sources and sinks of liquid inside S, the flux through the surface can be calculated by adding up the volume rate of liquid added by the sources and subtracting the rate of liquid drained off by the sinks. The volume rate of flow of liquid through a source or sink (with the flow through a sink given a negative sign) is equal to the divergence of the velocity field at the pipe mouth, so adding up (integrating) the divergence of the liquid throughout the volume enclosed by S equals the volume rate of flux through S. This is the divergence theorem.^[2]

The divergence theorem is employed in any conservation law which states that the total volume of all sinks and sources, that is the volume integral of the divergence, is equal to the net flow across the volume's boundary.^[3]

Mathematical statement

Suppose V is a subset of ${\displaystyle \mathbb {R} ^{n}}$ (in the case of n = 3, V represents a volume in three-dimensional space) which is compact and has a piecewise smooth boundary S (also indicated with ${\displaystyle \partial V=S}$). If F is a continuously differentiable vector field defined on a neighborhood of V, then:^[4][5]

${\displaystyle \iiint \limits _{V}\left(\mathbf {\nabla } \cdot \mathbf {F} \right)\,\mathrm {d} V=}$ ${\displaystyle \scriptstyle S}$ ${\displaystyle (\mathbf {F} \cdot \mathbf {\hat {n}} )\,\mathrm {d} S.}$

The left side is a volume integral over the volume V, the right side is the surface integral over the boundary of the volume V. The closed, mesurable set ${\displaystyle \partial V}$ is oriented by outward-pointing normals, and ${\displaystyle \mathbf {\hat {n}} }$ is the outward pointing unit normal at almost each point on the boundary ${\displaystyle \partial V}$. (${\displaystyle \mathrm {d} \mathbf {S} }$ may be used as a shorthand for ${\displaystyle \mathbf {n} \mathrm {d} S}$.) In terms of the intuitive description above, the left-hand side of the equation represents the total of the sources in the volume V, and the right-hand side represents the total flow across the boundary S.

Informal derivation

The divergence theorem follows from the fact that if a volume V is partitioned into separate parts, the flux out of the original volume is equal to the sum of the flux out of each component volume.^[6][7] This is true despite the fact that the new subvolumes have surfaces that were not part of the original volume's surface, because these surfaces are just partitions between two of the subvolumes and the flux through them just passes from one volume to the other and so cancels out when the flux out of the subvolumes is summed.

See the diagram. A closed, bounded volume V is divided into two volumes V₁ and V₂ by a surface S₃ (green). The flux Φ(V_i) out of each component region V_i is equal to the sum of the flux through its two faces, so the sum of the flux out of the two parts is

${\displaystyle \Phi (V_{\text{1}})+\Phi (V_{\text{2}})=\Phi _{\text{1}}+\Phi _{\text{31}}+\Phi _{\text{2}}+\Phi _{\text{32}}}$

where Φ₁ and Φ₂ are the flux out of surfaces S₁ and S₂, Φ₃₁ is the flux through S₃ out of volume 1, and Φ₃₂ is the flux through S₃ out of volume 2. The point is that surface S₃ is part of the surface of both volumes. The "outward" direction of the normal vector ${\displaystyle \mathbf {\hat {n}} }$ is opposite for each volume, so the flux out of one through S₃ is equal to the negative of the flux out of the other

${\displaystyle \Phi _{\text{31}}=\iint _{S_{3}}\mathbf {F} \cdot \mathbf {\hat {n}} \;\mathrm {d} S=-\iint _{S_{3}}\mathbf {F} \cdot (-\mathbf {\hat {n}} )\;\mathrm {d} S=-\Phi _{\text{32}}}$

so these two fluxes cancel in the sum. Therefore

${\displaystyle \Phi (V_{\text{1}})+\Phi (V_{\text{2}})=\Phi _{\text{1}}+\Phi _{\text{2}}}$

Since the union of surfaces S₁ and S₂ is S

${\displaystyle \Phi (V_{\text{1}})+\Phi (V_{\text{2}})=\Phi (V)}$

This principle applies to a volume divided into any number of parts, as shown in the diagram.^[7] Since the integral over each internal partition (green surfaces) appears with opposite signs in the flux of the two adjacent volumes they cancel out, and the only contribution to the flux is the integral over the external surfaces (grey). Since the external surfaces of all the component volumes equal the original surface.

${\displaystyle \mathrm{\Phi <!--\; \Phi \; -->}(V)=\underset{V_{\text{i}}\subset <!--\; \subset \; -->V}{\sum <!--\; \sum \; -->}\mathrm{\Phi <!--\; \Phi \; -->}(V_{\text{i}}}$Zdroj:https://en.wikipedia.org?pojem=Divergence_theorem
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