A | B | C | D | E | F | G | H | CH | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | Y | Z | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9
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| Turnout | 82.60%
 5.66%[1] | ||||||||||||||||||||||||||||||||
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 County Results
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| Elections in Washington |
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The 1992 United States presidential election in Washington took place on 3 November 1992, as part of the 1992 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.
Washington was won by Governor Bill Clinton (D-Arkansas) with 43.41% of the popular vote over incumbent President George H. W. Bush (R–Texas) with 31.97%. Businessman Ross Perot (I-Texas) finished in third, with 23.68% of the popular vote.[2] Clinton ultimately won the national vote, defeating incumbent President Bush.[3]
As of the 2020 presidential election[update], this is the last election in which Okanogan County has voted for a Democratic Presidential nominee.[4] It was also the first occasion since Franklin D. Roosevelt’s 1936 landslide that Whitman County had supported a Democratic presidential candidate, as well as the first time that King County was the most Democratic in the state, a trend that has continued in every presidential election since.[5]